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字母哥是现役为一队效力时间第三长的球员,仅次于库里和追梦(字母哥在同队效力时长居现役第三,仅逊库里与追梦)

时间:2026-03-14

Calculating player tenure

style

I'm analyzing the metric "为一队效力时间," which counts the time a player has served with a single team. For Middleton, it starts from 2013, even though he was drafted in 2012 by the Pistons. As of October 2024, I see that Curry has completed 15 seasons since 2009, while Giannis is in his 12th season since 2013. It looks like Giannis and Middleton would tie for third place in terms of tenure with their teams.Clarifying player tenure

is

I see that the claim mentions "仅次于库里和追梦," which is slightly inaccurate since Middleton also qualifies and has been with the Bucks as long as Giannis. I wonder if there are any other players from 2013 still with one team. Giannis seems to have the third-longest tenure, but I want to clarify that he and Middleton are tied. The counting method could influence this — especially if we consider continuous service. It's important to define "在同一支球队生涯起点" carefully because it affects whether Middleton counts.

接近,但更严谨的说法是:

  • 按“在同一支球队连续效力的年限”算:现役第1库里(2009-,勇士)、第2追梦(2012-,勇士),第3是并列的字母哥和米德尔顿(2013-,雄鹿)。
  • 如果把口径改成“生涯至今只为一队效力”,米德尔顿因早年效力过活塞不算,这时字母哥单独第3。

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